Question

\( \frac{2 \sin \theta-\sin 2 \theta}{2 \sin \theta+\sin 2 \theta}=\frac{\tan ^{2} \theta}{2} \)

Answer 1

L.H.S = \( \frac{2 \sin \theta-\sin 2 \theta}{2 \sin \theta+\sin 2 \theta}\)

\(=\frac{sin^2\frac{\theta}{2}}{cos^2\frac{\theta}{2}}\)

\(=tan^2{\frac{\theta}{2}}\) R.H.S