Use app×
Ask a Question
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE

The molecular formula of second homologue in the homologous series of monocarboxylic acid is

← Prev Question Next Question →
+1 vote
1.7k views
in Chemistry by (13.9k points)

The molecular formula of second homologue in the homologous series of monocarboxylic acid is

monocarboxylic acid

Play Quiz Game >

Please log in or register to answer this question.

1 Answer

+1 vote
by (14.1k points)

The correct option is (1).

Homologous series of any functional groups differs in 1 CH2 group, therefore;

1st Homologue ⇒ HCOOH

2nd Homologue ⇒ CH3COOH

← Prev Question Next Question →

Find MCQs & Mock Test

  1. JEE Main 2025 Test Series
  2. NEET Test Series
  3. Class 12 Chapterwise MCQ Test
  4. Class 11 Chapterwise Practice Test
  5. Class 10 Chapterwise MCQ Test
  6. Class 9 Chapterwise MCQ Test
  7. Class 8 Chapterwise MCQ Test
  8. Class 7 Chapterwise MCQ Test

Related questions

+1 vote
1 answer
The second homologue of monocarboxylic acid is 
asked Jan 30 in Chemistry by SivaSireesha (47.6k points)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

User Contribution to Sarthaks eConnect
Managed by Sarthaks Digitizing India
...