Correct option is (A) 900
Given A.P. is \(1,3,5,7, \ldots\)
Number of terms of A.P is \(n=30\)
First term \((a) = 1\)
Common difference \((d)=3-1=2\)
We know that sum of n term of an AP is given by:
\(S_{n}=\frac{n}{2}[2 a+(n-1) d]\)
\(S_{30} =\frac{30}{2}[2 \times 1+(30-1) 2]\)
\(=15[2+60-2] \)
\(=15 \times 60\)
\( =900\)
Hence, the sum of given A.P. is 900.
