If α and β are the zeroes of the polynomial p(x) = x^2 - 3x - 4 then the value of

Question

If \(\alpha\) and \(\beta\) are the zeroes of the polynomial \(p(x) = x^2 - 3x - 4\) then the value of \(\frac 43(\alpha + \beta)\) is

(A) 4

(B) 3

(C) -3

(D) 1

Answer 1

Correct option is (A) 4

\(\alpha\) and \(\beta\) are the zeroes of the polynomial.

\(x^2-3 x-4=0\)

So, \(a=1, b=-3\) and \(c=-4\)

\(\Rightarrow \alpha+\beta =\frac{-b}{a}\)

\(=\frac{-(-3)}{1}\)

\(=3\)

Now,

\( \frac{4}{3}(\alpha+\beta) \)

\(= \frac{4}{3} \times 3\)

\(= 4\)