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+1 vote
882 views
in Limit, continuity and differentiability by (41.4k points)

The slope of tangent to the curve x = t2 + 3t - 8, y = 2t2 - 2t - 5  at the point (2, −1) is

(A) 22/7 

(B) 6/7 

(C) − 6 

(D) None of these 

1 Answer

+2 votes
by (41.7k points)
selected by
 
Best answer

Answer is (B) 6/7

We have t = 2 for the point (2,−1). Therefore, for t = 2, we get

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