Question

The slope of the tangent to the curve x = t² + 3t – 8, y = 2t² – 2t – 5 at the point (2, -1) is

(A) \(\frac{22}{7}\)

(B) \(\frac{6}{7}\)

(C) \(\frac{7}{6}\)

(D) \(\frac{-6}{7}\)

Answer 1

Answer is (B)