Correct option (C) 4 : 3
Let Sn and S'n be the sums of n terms of two AP’s and T11 and T11 be the respective 11th terms. Then
Now put n = 21. We get
Note: If ratio of sum of n terms of two APs is given in terms of n and ratio of their pth terms is to be found then put n = 2p - 1. Here we put n = 11 x 2 - 1 = 21.