Question

The sum of the series 1/2 + 1/3 + 1/6 + ....to 9  terms is 

(A)   - (5/6)

(B)   -(1/2)

(C)   1

(D)   - (3/2)

Answer 1

Correct option (D)  -(3/2)

Given series  1/2 + 1/3 + 1/6

Here a = 1/2, common difference d = -1/6 and n = 9. So