We know that the incident ray and the reflected ray equally inclined to the normal at A. Let A = (h, 0)
If AC makes an angle (-) with the normal at A, then it makes an angled (90° – θ) with positive x-axis and AB makes an angle (90° + θ) with positive x-axis.
Now, slope of AB = tan (90° + θ) = – cot θ
Slope of AC = tan (90° – θ) = cot θ
∴ Slope of AB + slope of AC = θ