Question

There are four men and six women on the city council. If one council member is selected for a committee at random, how likely is it that it is a woman?

Answer 1

Number of members on the city council 

= 4 + 6 = 10 

n(S)= ¹⁰C₁ =10 

Let A: ‘selected member is a woman’ 

⇒n(A)= ⁶C₁ = 6 

∴ Required probability

= P(A) = n(A)/n(S) = 6/10 = 3/5