Given,
f(x)= 2x4 + x3 – 14x2 – 19x – 6
If the two zeros of the polynomial are -2 and -1, then its factors are (x + 2) and (x + 1)
⇒ (x+2)(x+1) = x2 + x + 2x + 2
= x2 + 3x +2 …… (i)
This means that (i) is a factor of f(x). So, performing division algorithm we get,
The quotient is 2x2 – 5x – 3.
⇒ f(x)= (2x2 – 5x – 3)( x2 + 3x +2)
For obtaining the other 2 zeros of the polynomial
We put,
2x2 – 5x – 3 = 0
⇒ (2x + 1)(x – 3) = 0
∴ x = -1/2 or 3
Hence, all the zeros of the polynomial are -2, -1, -1/2 and 3.