Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
2.4k views
in Polynomials by (56.3k points)

Obtain all zeroes of f(x) = x3 + 13x2 + 32x + 20, if one of its zeros is -2.

1 Answer

+1 vote
by (30.5k points)
selected by
 
Best answer

Given, 

f(x)= x3 + 13x2 + 32x + 20 

And, -2 is one of the zeros. So, (x + 2) is a factor of f(x), 

Performing division algorithm, we get

⇒ f(x) = (x2 + 11x + 10)( x + 2) 

So, putting x2 + 11x + 10 = 0 we can get the other 2 zeros. 

⇒ (x + 10)(x + 1) = 0 

∴ x = -10 or -1 

Hence, all the zeros of the polynomial are -10, -2 and -1.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...