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Prove that only one out of three consecutive positive integers is divisible.

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Let three consecutive positive integers are n, n + 1,

n + 2 respectively.

We know that n is of the form 3q or 3q + 1 or 3 q + 2.

Now following cases are possible.

Case 1.

when n = 3q which is divisible by 3

n + 1 = 3q + 1, Not divisible by 3

n + 2 = 3q + 2, Not divisible by 3

In this case n is divisible by 3 but (n + 1) and (n + 2) are not divisible by 3

Case 2.

When n = 3q + 1

In this positive Which is divisible by 3 but n and n + 1 are not divisible by 3.

Case 3.

When n = 3q + 2

In this position divisible by 3 but or (n + 2) are not divisible by 3

Hence out of n, (n + 1) and (n + 2) one is divisible by 3.

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