Given pair of linear equations is
8x + 5y = 9 …(i)
And 3x + 2y = 4 …(ii)
On multiplying Eq. (i) by 2 and Eq. (ii) by 5 to make the coefficients of y equal, we get the equation as
16x + 10y = 18 …(iii)
15x + 10y = 20 …(iv)
On subtracting Eq. (iii) from Eq. (iv), we get
15x + 10y – 16x – 10y = 20 – 18
⇒ – x = 2
⇒ x = – 2
On putting x = – 2 in Eq. (ii), we get
3x + 2y = 4
⇒ 3( – 2) + 2y = 4
⇒ – 6 + 2y = 4
⇒ 2y = 4 + 6
⇒ 2y = 10
y = 10/2 = 5
Hence, x = 2 and y = 5 , which is the required solution.
