Equation of the line in two point form is \(\frac {y-y_1}{y_2-y_1} = \frac {x-x_1}{x_2-x_1}\)
Equation of side AB is \(\frac {y-4}{3-4} = \frac {x-1}{2-1}\)
y – 4 = -1(x – 1)
y – 4 = -x + 1
x + y = 5
Equation of side BC is \(\frac {y-3}{6-3} = \frac {x-2}{1-2}\)
-1(y – 3) = 3(x – 2)
-y + 3 = 3x – 6
∴ 3x + y = 9
Since both the points A and C have same x co-ordinates i.e. 1
the points A and C lie on a line parallel to Y-axis.
∴ The equation of side AC is x = 1.
