Question

The equivalent weight of MnSO₄ is half of its molecular weight when it is converted to

(a) Mn₂O₃

(b) MnO₂

(c) MnO₄

(d) MnO₄^2-

Answer 1

Correct option is (b) MnO₂

\(\overset{+2} {Mn}SO_4^{2-} \longrightarrow \overset{+4}{Mn}O_2 + 2e^-\)

Here, change in oxidation of Mn = 2.

So, n−factor = 2.

Equivalent weight = \(\frac M2\)

Therefore, the equivalent weight of MnSO₄​ is half of its molecular weight when it is converted to MnO_2​.