Question

The equivalent weight of K₂Cr₂O₇ as an oxidising agent in acid medium is

(a) 2/3 of its mol. wt.

(b) 1/3 of its mol. wt.

(c) 1/6 of its mol. wt.

(d) 1/2 of its mol. wt.

Answer 1

Correct option is (c) 1/6 of its mol. wt.

Oxidation half reaction of K2Cr2O7 in acidic medium is :

K₂Cr₂O₇ + 14H⁺ + 6e^- → 2K⁺ + 2Cr³⁺ + 7H₂O

Eq. mass of K₂Cr₂O₇ = \(\frac{\text{Mol. mass}}6\)