Question

In the following reaction, which choice has value twice that of the equivalent weight of the oxidising agent. 

SO₂ + H₂O → 3S + 2H₂O 

(a) 16

(b) 48

(c) 64

(d) 32

Answer 1

Correct option is (d) 32

SO₂ + H₂O → 3S + 2H₂O

Eq. wt. of SO₂ in the reaction = \(\frac{\text{Mol. mass of }SO_2}{\text{change in oxidation state}}\)

\(= \frac{64}{4}\)

\(= 16\)

Twice of 16 will be 32.