Question

If 1 is one zero of the polynomial \(p(x) = ax^2 - 3(a - 1) x - 1\) then value of a is

(A) 3

(B) 1

(C) 0

(D) 2

Answer 1

Correct option is (B) 1

Given: \(p(x)=a x^2-3(a-1) x-1\)

One of the zero = 1

As one of the zeroes is 1, substituting it in the polynomial

\(\Rightarrow p(1)=a(1)^2-3(a-1) \times 1-1=0\)

\(a-3 a+3-1=0\)

\(-2 a+2=0\)

\(-2a = -2\)

\(a = \frac{-2}{-2} = 1\)