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Prove that 7 – √5 is an irrational number.

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Best answer

Let 7 – √5 is a rational number.

7 + √5 = a/b, b ≠ 0 …(i)

Where a and b co-prime integer number.

Equation (i) can be written as

√5 = a/b – 7

or √5 = (a - 7b)/b ….(ii)

Since, a and b are integers. 

So (a - 7b)/b will be rational number, so from equation (ii) we find that √5 is a rational number.

But we know that √5 is a irrational number.

So this result is contradicted.

So our hypothesis is wrong.

Hence 7 + √5 is a rational number.

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