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in Determinants by (40.4k points)
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सिद्ध कीजिए कि \(\begin{vmatrix}1&1&1\\ a&b&c\\ a^3&b^3&c^3\end{vmatrix}\) = (b-c)(c-a)(a-b)(a+b+c)

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L.H.S. =  \(\begin{vmatrix}1&1&1\\ a&b&c\\ a^3&b^3&c^3\end{vmatrix}\) 

R1 के सापेक्ष प्रसार करने पर,

= (a – b) (b – c) [(b2 + c2+ bc) – (a2 + b2 + ab)]

= (a – b) (b – c) (b2 + c2+ bc – a2 – b2– ab)

= (a – b) (b – c) [bc + c2 – a2 – ab]

= (a – b) (b – c) [bc – ab + c2 – a2]

= (a – b) (b – c) [b(c – a) + (c2 – a2)]

= (a – b) (b – c) (c – a) (b + c + a)

= R.H.S.
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